Originally Posted by
Eric McArthur
Hi EmsE
Eric wrote:
Consider 7, “between frame” spaces occupied by bees; each space received 5mls of solution; a total of 35 mls of solution is delivered. A quick calculation of the amount of active ingredient delivered indicates that only 2.23/50 x 35 = 1.56 g of active ingredient is delivered. This is quite a short fall.
Take note of what Calum has written - and use what I wrote and his experience wisely -as and when! Talk to Ian Craig!
In the case mooted the colony will be under dosed, regardless! Look at the weight of active ingredient relative to the volume, 2.32 g is the 10 comb dosage!
Eric
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